CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    A 100 W bulb produces an electric field of \[2.9\text{ }V{{m}^{-1}}\]at a point 3 m away. If the bulb is replaced by 400 W bulb without distributing other conditions, then the electric field produced at the same point is

    A)  \[2.9\text{ }V{{m}^{-1}}\]        

    B)         \[3.5\text{ }V{{m}^{-1}}\]

    C)  \[5\text{ }V{{m}^{-1}}\]              

    D)         \[5.8\text{ }V{{m}^{-1}}\]

    E)  \[\text{1}\text{.45 }V{{m}^{-1}}\]

    Correct Answer: D

    Solution :

    When power becomes four times both S and 5 will get doubled. Hence,        \[{{E}_{2}}=5.8\,V/m\]


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