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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    The degree and order of the differential equation\[y=px+\sqrt[3]{{{a}^{2}}{{p}^{2}}+{{b}^{2}}},\]where\[p=\frac{dy}{dx},\]are respectively

    A)  3, 1                                       

    B)  1, 3

    C)  1, 1                       

    D)         3, 3

    E)  3, 2

    Correct Answer: B

    Solution :

    Given differential equation is \[y=px+\sqrt[3]{{{a}^{2}}{{p}^{2}}+{{b}^{2}}}\] where \[p=\frac{dy}{dx}\] \[\Rightarrow \]               \[(y-px)=\sqrt[3]{{{a}^{2}}{{p}^{2}}+{{b}^{2}}}\] Taking cube on both sides, we get                 \[{{(y-px)}^{3}}={{a}^{2}}{{p}^{2}}+{{b}^{2}}\]                 \[0-1,d=3\]


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