A) \[(-\infty ,-11)\cup (3,\infty )\]
B) \[(-\infty ,-10)\cup (2,\infty )\]
C) \[(-100,-11)\cup (1,\infty )\]
D) \[(0,5)\cup (-1,0)\]
E) \[(-5,0)\cup (3,7)\]
Correct Answer: A
Solution :
\[\frac{x+11}{x-3}>0\] \[\Rightarrow \] \[(x+11)(x-3)>0\] \[\Rightarrow \] \[x+11>0\]and \[(x-3)>0\] or \[x+11<0\]and \[x-3<0\] \[\Rightarrow \] \[x>-11\]and \[x>3\] or \[x<-11\]and \[x<3\] \[\Rightarrow \] \[x<-11\]and \[x>3\] \[\Rightarrow \] \[x\in (-\infty ,-11)\cup (3,\infty )\]You need to login to perform this action.
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