A) \[\frac{2\pi }{3}\]
B) \[\frac{\pi }{3}\]
C) \[\frac{\pi }{2}\]
D) \[\pi \]
E) \[2\pi \]
Correct Answer: A
Solution :
We have \[f(\theta )=4+4{{\sin }^{3}}\theta -3\sin \theta \] \[=4-\sin 3\theta \] \[\therefore \]Period of\[f=\frac{2\pi }{3}\] \[\left( \because Period\text{ }of\,\sin ax=\frac{2\pi }{|a|} \right)\]You need to login to perform this action.
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