A) \[y=x+1\]
B) \[y=x-1\]
C) \[y=3x-5\]
D) \[y=x\]
E) \[y=-x\]
Correct Answer: A
Solution :
Equation of line AB is \[y-7=\frac{4-7}{3-3}(x-3)\] \[\Rightarrow \] \[(x-3)=0\] ...(i) and equation of line BC is \[y-4=\frac{4-4}{5-3}(x-3)\] \[\Rightarrow \] \[y-4=0\] \[\therefore \]Equation of the bisector of angle ABC is \[\frac{x-3}{\sqrt{{{1}^{2}}}}=\pm \left( \frac{y-4}{\sqrt{{{1}^{2}}}} \right)\] \[\Rightarrow \] \[x-3=\pm (y-4)\] \[\Rightarrow \] \[x-y+1=0\] \[\Rightarrow \]You need to login to perform this action.
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