A) \[8x-y+5z-8=0\]
B) \[8x+y-5z-7=0\]
C) \[x-8y+3z+6=0\]
D) \[8x+y-5z+7=0\]
E) \[x+y+z-6=0\]
Correct Answer: B
Solution :
The equation of plane containing the line \[\frac{x-1}{2}=\frac{y+1}{-1}=\frac{z}{3}\] and \[\frac{x}{2}=\frac{y-2}{-1}=\frac{x+1}{3}\] The required equation is \[\left| \begin{matrix} x-1 & (y+1) & 3 \\ x & y-2 & 3+1 \\ 2 & -1 & 3 \\ \end{matrix} \right|=0\] \[\Rightarrow \]\[(x-1)(3y-6+z-1)-(y+1)\] \[(3x-2z-2)+z(-x-2y+4)=0\] \[-5x-3y-z+5+2y-3x+2z+2+4z=0\] \[\Rightarrow \] \[-8x-y+5z+7=0\] \[\Rightarrow \] \[8x+y-5z-7=0\]You need to login to perform this action.
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