A) 3, 1
B) 1, 3
C) 1, 1
D) 3, 3
E) 3, 2
Correct Answer: B
Solution :
Given differential equation is \[y=px+\sqrt[3]{{{a}^{2}}{{p}^{2}}+{{b}^{2}}}\] where \[p=\frac{dy}{dx}\] \[\Rightarrow \] \[(y-px)=\sqrt[3]{{{a}^{2}}{{p}^{2}}+{{b}^{2}}}\] Taking cube on both sides, we get \[{{(y-px)}^{3}}={{a}^{2}}{{p}^{2}}+{{b}^{2}}\] \[0-1,d=3\]You need to login to perform this action.
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