A) \[-1\]
B) 0
C) 1
D) 2
E) 3
Correct Answer: C
Solution :
Let 1 and 2 be root of equation \[{{x}^{2}}-bx+c=0\] \[{{1}^{2}}-b\times 1+c=0\] \[b-c=1\] ...(i) Similarly, \[\Rightarrow \] \[22-b{{x}^{2}}+c=0\] \[\Rightarrow \] \[2b-c=4\] ...(ii) Solving Eqs. (i) and (ii), we get \[b=3,\text{ }c=2\] \[\therefore \] \[{{b}^{2}}-4c={{3}^{2}}-4\times 2=9-8=1\]You need to login to perform this action.
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