A) 5
B) 1
C) 2
D) 3
E) 4
Correct Answer: D
Solution :
The sum of coefficient in the expansion of \[{{({{a}^{2}}{{x}^{2}}-6ax+11)}^{10}}=1024\] \[\Rightarrow \] \[{{({{a}^{2}}.1+6a.1+11)}^{10}}={{2}^{10}}\] (\[\because \]sum of coefficient in\[{{(x+y)}^{n}}\]is\[{{(1+1)}^{n}}={{2}^{n}}\]) \[\Rightarrow \] \[{{a}^{2}}-6a+11=2\] \[\Rightarrow \] \[{{a}^{2}}-6a+9=0\] \[\Rightarrow \] \[a=3,3\]
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