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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    The period of the function\[f(\theta )=4+4{{\sin }^{3}}\theta -3\sin \theta \]is

    A)  \[\frac{2\pi }{3}\]                                           

    B)  \[\frac{\pi }{3}\]

    C)  \[\frac{\pi }{2}\]                             

    D)         \[\pi \]

    E)  \[2\pi \]

    Correct Answer: A

    Solution :

    We have \[f(\theta )=4+4{{\sin }^{3}}\theta -3\sin \theta \] \[=4-\sin 3\theta \] \[\therefore \]Period of\[f=\frac{2\pi }{3}\] \[\left( \because Period\text{ }of\,\sin ax=\frac{2\pi }{|a|} \right)\]


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