CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    The area of the triangle formed by the points (2, 2), (5, 5), (6, 7) is equal to (in square units)

    A)  9                                            

    B)  5

    C)  10                         

    D)         3

    E)  14

    Correct Answer: D

    Solution :

    Required Area \[=\frac{1}{2}[2(5-7)+5(7-2)+6(2-5)]\] \[=\frac{1}{2}[-4+25-18]\] \[=\frac{3}{2}sq\text{ }unit\]


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