A) 2 V
B) 1 V
C) 3 V
D) 1.5 V
E) 0.5 V
Correct Answer: A
Solution :
Charge across the combination of\[2\mu F\]and \[3\mu F=\]charge across\[3\mu F\]. \[\therefore \] \[\frac{2\times 3}{2+3}\times 5=3\times {{V}_{1}}\] \[{{V}_{1}}=2\,V\]You need to login to perform this action.
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