A) \[{{10}^{18}}\]
B) \[{{10}^{15}}\]
C) \[{{10}^{6}}\]
D) \[{{10}^{9}}\]
E) \[{{10}^{12}}\]
Correct Answer: E
Solution :
\[qE=mg\] or \[ne\times E=mg\] \[n\times 1.6\times {{10}^{-19}}\times 100=1.6\times {{10}^{-6}}\times 10\] \[n={{10}^{12}}\]You need to login to perform this action.
You will be redirected in
3 sec