A) \[\frac{100}{3}J\]
B) \[100J\]
C) \[\frac{200}{3}J\]
D) \[150J\]
E) \[50J\]
Correct Answer: D
Solution :
\[\beta =\frac{{{\theta }_{2}}}{{{\theta }_{1}}-{{\theta }_{2}}}\] \[\frac{1}{3}=\frac{{{\theta }_{2}}}{200-{{\theta }_{2}}}\] \[{{\theta }_{2}}=50\] \[W=200-50=150\text{ }J\]
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