A) 5
B) 15
C) 45
D) 20
E) 25
Correct Answer: D
Solution :
The total energy \[=\frac{1}{2}k{{A}^{2}}\] \[u=\frac{1}{2}k{{A}^{2}}\] Or \[{{A}^{2}}=\frac{8}{800}\] Or \[{{A}^{2}}=\frac{1}{100}\] Or \[A=\frac{1}{10}=0.1\,m\] \[{{a}_{\max }}={{\omega }^{2}}A=\frac{k}{m}.A\] \[=\frac{800}{4}\times 0.1\] \[{{a}_{\max }}=20\,m/{{s}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
