A) (I) > (II) > (III) > (IV)
B) (II) > (III) > (I) > (IV)
C) (III) > (IV) > (II) > (I)
D) (IV) > (III) > (II) > (I)
E) (III) > (IV) > (I) > (II)
Correct Answer: C
Solution :
The correct order of decreasing acidity is \[\underset{(III)}{\mathop{CH\equiv CH}}\,>\underset{(IV)}{\mathop{CH\equiv C-C{{H}_{3}}}}\,>\underset{(II)}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\] \[>\underset{(I)}{\mathop{C{{H}_{3}}-C{{H}_{3}}}}\,\] Hydrogen atoms attached to sp-hybridised carbon atom are most acidic, followed by those attached to\[s{{p}^{2}}\]hybridised carbon atom and those attached to\[s{{p}^{3}}\]hybridised carbon are least acidic.
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