A) Neo-pentyl
B) Tert-butyl
C) \[Iso-\]propyl
D) Ethyl
E) Methyl
Correct Answer: B
Solution :
On the basis of hyperconjugation, stability order of different alkyl carbocations is \[3{}^\circ >2{}^\circ >1{}^\circ >methyl\] In t-butyl cation, the C-atom bearing the positive charge is attached to three methyl groups, thus it will have maximum hyperconjugative structures, which give it maximum stability.
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