A) \[{{F}_{3}}CCOOH\]
B) \[F-C{{H}_{2}}COOH\]
C) \[C{{H}_{3}}COOH\]
D) \[C{{H}_{3}}C{{H}_{2}}COOH\]
E) \[{{(C{{H}_{3}})}_{2}}CH-COOH\]
Correct Answer: E
Solution :
The acidity of carboxylic acids depends upon the nature of the alkyl group attached to\[COOH\]. The presence of an electron-withdrawing (\[-I\]effect) group weakens the \[OH\]bond in the acid and increases the acidity, while the presence of an electron releasing (\[+I\]effect) group strengthens the \[OH\] bond of acid and thus, decreases the acidity. Thus, the weakest acid is, \[\underset{2-methylpropanoic\text{ }acid}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}\,-COOH}}\,\]
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