A) \[-130\]
B) \[-\,65\]
C) + 130
D) \[-\,334\]
E) + 334
Correct Answer: A
Solution :
\[{{H}_{2}}(g)+{{O}_{2}}(g)\xrightarrow{{}}{{H}_{2}}{{O}_{2}}(g)\] \[\Delta {{H}_{reaction}}=B{{E}_{reac\tan ts}}-B{{E}_{products}}\] \[=[BE(H-H)+BE(O=O)]\] \[-2BE(O-H)+BE(O-O)]\] \[=[438+498]-[2\times 464+138]\] \[=936-1066=-130\text{ }kJ\text{ }mo{{l}^{-1}}\]You need to login to perform this action.
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