CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2010

  • question_answer
    A 600 W mercury lamp emits monochromatic radiation of wavelength 331.3 nm. How many photons are emitted from the lamp per second? (\[h=6.626\times {{10}^{-34}}Js;\]velocity   of   light\[=3\times {{10}^{8}}m{{s}^{-1}}\])

    A)  \[1\times {{10}^{19}}\]                                

    B)  \[1\times {{10}^{20}}\]

    C)  \[1\times {{10}^{21}}\]                

    D)         \[1\times {{10}^{23}}\]

    E)  \[1\times {{10}^{22}}\]

    Correct Answer: C

    Solution :

    Given, power = 600 W \[\lambda =331.3\text{ }nm=331.3\times {{10}^{-9}}m\] \[h=6.626\times {{10}^{-34}}J\] \[c=3\times {{10}^{8}}m{{s}^{-1}}\] \[t=1\text{ }s\] \[Power=\frac{energy}{time}\]                 \[=\frac{nhv}{t}=\frac{nhc}{\lambda t}\] or            \[n=\frac{power\times \lambda t}{hc}\]                                     \[=\frac{600\times 331.3\times {{10}^{-9}}\times 1}{6.626\times {{10}^{-34}}\times 3\times {{10}^{8}}}\] \[n=1\times {{10}^{21}}\]


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