CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    Which of the following is the correct method of preparation of methyl fluoride?

    A)  \[C{{H}_{4}}+HF\xrightarrow{{}}\]

    B)        \[C{{H}_{3}}OH+HF\xrightarrow{{}}\]

    C)  \[C{{H}_{4}}+{{F}_{2}}\xrightarrow{{}}\]

    D)  \[C{{H}_{3}}Br+AgF\xrightarrow{{}}\]

    E)  \[C{{H}_{3}}N{{H}_{2}}+HF\xrightarrow{{}}\]

    Correct Answer: D

    Solution :

    Fluorination of hydrocarbons with pure\[{{F}_{2}}\]gas occurs explosively. Thus, alkyl fluorides are more conveniently prepared indirectly by heating suitable chloro or bromoalkanes with inorganic fluorides. \[\underset{bromomethane}{\mathop{C{{H}_{3}}Br}}\,~+AgF\xrightarrow[{}]{{}}~\underset{fluoromethane}{\mathop{C{{H}_{3}}F}}\,~+\text{ }AgBr\] This reaction is called Swarts reaction.


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