A) \[x-y=-1\]
B) \[x-y=3\]
C) \[x+y=3\]
D) \[x+y=1\]
E) \[x+y=-1\]
Correct Answer: B
Solution :
The equation of the line passing through the points\[(-2,3)\]and\[(6,-5)\]is \[(y-3)=\frac{-5-3}{6+2}(x+2)\] \[\Rightarrow \] \[(y-3)=-1(x+2)\] \[\Rightarrow \] \[y-3=-x-2\] \[\Rightarrow \] \[y=-x+1\] ?..(i) Now, the slope of perpendicular bisector of this line is\[=\frac{-1}{(-1)}=1\] and the perpendicular bisector passing through the mid point of this line is\[(2,-1)\]. Then, equation of perpendicular bisector is \[(y+1)=1(x+2)\] \[\Rightarrow \] \[y+1=x-2\] \[\Rightarrow \] \[x-y=3\]You need to login to perform this action.
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