2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    If\[2y=si{{n}^{-1}}(x+5y),\]then\[\frac{dx}{dy}\]is equal to

    A)  \[cos\text{ }2y-5\]        

    B)  \[2cosy+5\]      

    C)         \[cos\text{ }2y+5\]        

    D)         \[2cos2y+5\]

    E)  \[2cos2y-5\]

    Correct Answer: E

    Solution :

    \[2y={{\sin }^{-1}}(x+5y)\] \[\Rightarrow \] \[\sin 2y=x+5y\] \[\Rightarrow \] \[x=\sin 2y-5y\] On differentiating w.r.t. y, \[\Rightarrow \]               \[\frac{dx}{dy}=2\cos 2y-5\]      


You need to login to perform this action.
You will be redirected in 3 sec spinner