CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    A car moves a distance of 200 m. It covers first half of the distance at speed \[60\,\,km{{h}^{-1}}\] and the second half at speed v. If the average speed is \[40\,\,km{{h}^{-1}},\] the value of v is

    A)  \[30\,km{{h}^{-1}}\]                                     

    B)  \[13\,km{{h}^{-1}}\]        

    C)             \[60\,km{{h}^{-1}}\]                     

    D)         \[40\,km{{h}^{-1}}\]

    E)  \[20\,km{{h}^{-1}}\]

    Correct Answer: A

    Solution :

    Average velocity \[=\frac{2{{v}_{1}}{{v}_{2}}}{{{v}_{1}}+{{v}_{2}}}\] Given \[{{v}_{av}}=40\text{ }km{{h}^{-1}}\] \[{{v}_{1}}=60\text{ }km{{h}^{-1}}\] and        \[{{v}_{2}}=?\]                 \[40=\frac{2\times 60\times {{v}_{2}}}{60+{{v}_{2}}}\] \[{{v}_{2}}=30\text{ }km{{h}^{-2}}\]


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