CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    A bus begins to move with an acceleration of \[1\,\,m{{s}^{-2}}\]. A man who is 48 m behind the bus starts running at 10 ms  to catch the bus. The man will be able to catch the bus after

    A)  6s                          

    B)         5 s                         

    C)  3 s                         

    D)         7 s

    E)  8s

    Correct Answer: E

    Solution :

    Given \[a=1\text{ }m{{s}^{-2}},\text{ s}=48\text{ }m\] By the equation of motion \[40+\frac{1}{2}a{{t}^{2}}=10t\] \[t=8s\]


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