CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    A particle is moving with constant acceleration from A to Bin a straight line AB. If u and v are the velocities at A and B respectively then its velocity at the midpoint C will be

    A) \[{{\left( \frac{{{u}^{2}}+{{v}^{2}}}{2u} \right)}^{2}}\]    

    B)        \[\frac{u+v}{2}\]                             

    C) \[\frac{v-u}{2}\]                              

    D)        \[\sqrt{\frac{{{u}^{2}}+{{v}^{2}}}{2}}\]

    E) \[\sqrt{\frac{{{v}^{2}}-{{u}^{2}}}{2}}\]

    Correct Answer: D

    Solution :

    We have standard result for this type of velocity \[=\sqrt{\frac{{{u}^{2}}+{{v}^{2}}}{2}}\]


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