A) \[1-i\]
B) \[i\]
C) \[-i\]
D) \[2i\]
E) \[-2i\]
Correct Answer: C
Solution :
Equation, \[{{x}^{2}}-x+(1-i)=0\] and one root is given, say\[a=1+i\]and second root is\[\beta \]. Since, the given root in complex form so, the other root is also complex form. Sum of the roots\[=\alpha -\beta =-(-1)\] \[\beta =1-\alpha =1-(1+i)=-i\] \[\therefore \] The other root is\[-i\].
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