A)
B) \[(-\infty ,0)\]
C) \[(-1,0)\]
D) \[(0,1)\]
E) \[(1,3)\]
Correct Answer: D
Solution :
\[3{{x}^{2}}+2x+{{a}^{2}}-a=0\] The condition for a quadratic equation have both roots are an opposite sign is constant term\[<0\] \[\Rightarrow \] \[({{a}^{2}}-a)<0\] \[\Rightarrow \] \[a(a-1)<0\] \[\Rightarrow \] \[a\in (0,1)\]You need to login to perform this action.
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