A) \[x-3y=0\]
B) \[x+3y=0\]
C) \[3x+y=0\]
D) \[3x-y=0\]
E) \[x+2y=0\]
Correct Answer: A
Solution :
The equation of circle is \[{{x}^{2}}-{{y}^{2}}-6x+2y=0\] centre\[=(3,-1)\] Since, the equation of diameter passes through the centre of the circle, then the coordinates of centre will satisfy the equation of diameter. From option, only the equation is \[x-3y=0\].
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