question_answer

The straight line passing through the point \[(1,0,-2)\] and perpendicular to the plane \[x-2y+5z-7=0\]is

A)  \[\frac{x-1}{1}=\frac{y}{0}=\frac{z-5}{-2}\]

B)         \[\frac{x-1}{5}=\frac{y}{-2}=\frac{z+2}{1}\]

C)  \[\frac{x-5}{-2}=\frac{y-1}{-5}=\frac{z}{1}\]

D)         \[\frac{x-1}{-1}=\frac{y}{-2}=\frac{z-2}{5}\]

E)  \[\frac{x-1}{1}=\frac{y}{-2}=\frac{z+2}{5}\]

Correct Answer: E

Solution :

A straight line passing through the point and perpendicular to the plane. ie, this line is normal to the plane. So, the equation of line in symmetric form is