A) \[\sqrt{\frac{10gh}{7}}\]
B) \[\sqrt{\frac{4gh}{7}}\]
C) \[\sqrt{\frac{4gh}{3}}\]
D) \[\sqrt{2gh}\]
E) \[\sqrt{gh}\]
Correct Answer: E
Solution :
For a ring\[{{k}^{2}}={{r}^{2}}\]then \[{{v}^{2}}=\frac{2gh}{1+{{k}^{2}}/{{r}^{2}}}=\frac{2gh}{2}=gh\] \[v=\sqrt{gh}\]
You need to login to perform this action.
You will be redirected in
3 sec
