A) \[0.1\,m{{s}^{-1}}\]
B) \[1.133\,\,m{{s}^{-1}}\]
C) \[0.4\,m{{s}^{-1}}\]
D) \[0.2\,\,m{{s}^{-1}}\]
E) \[0.3\,\,m{{s}^{-1}}\]
Correct Answer: A
Solution :
We have\[v=\frac{2}{9}\frac{(\rho -\sigma ){{r}^{2}}g}{\eta }\] Here we can say \[v\propto (\rho -\sigma )\] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{{{\rho }_{1}}-\sigma }{{{\rho }_{2}}-\sigma }=0.1\]
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