A) \[2\pi a\]
B) \[a\]
C) \[\frac{a}{2\pi }\]
D) \[\frac{a}{\pi }\]
E) \[\frac{a}{\sqrt{2\pi }}\]
Correct Answer: E
Solution :
We have \[{{v}^{2}}=\rho gh\] \[{{a}^{2}}\sqrt{\rho gh}=\pi {{r}^{2}}\sqrt{\rho gh}\times 2\] \[r=\frac{\alpha }{\sqrt{2\pi }}\]
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