A) 1 : 2
B) 2 : 1
C) 1 : 3
D) 1: \[\sqrt{2}\]
E) 3 : 1
Correct Answer: B
Solution :
\[L=\frac{1}{2}g\cos {{60}^{o}}t_{1}^{2}\] ...(i) \[L\cos \theta =\frac{1}{2}gt_{2}^{2}\] ...(ii) \[\frac{t_{1}^{2}}{t_{2}^{2}}=\frac{1}{{{\cos }^{2}}{{60}^{o}}}=\frac{4}{1}\] \[{{t}_{1}}:{{t}_{2}}::2:1\]You need to login to perform this action.
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