A) \[\frac{mg}{(h+x)}\]
B) \[\frac{mg}{(h+2x)}\]
C) \[\frac{2mg(h+x)}{{{x}^{2}}}\]
D) \[\frac{mg}{(2h+x)}\]
E) \[\frac{2mg}{(h+x)}\]
Correct Answer: C
Solution :
Hence\[mg(h+x)=\frac{1}{2}k{{x}^{2}}\] \[k=\frac{2mg(h+x)}{{{x}^{2}}}\]You need to login to perform this action.
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