A) 4 : 1
B) 1 : 8
C) 8 : 1
D) 1 : 4
E) 1 : 2
Correct Answer: B
Solution :
We have\[{{T}^{2}}\propto {{R}^{3}}\] \[{{R}_{1}}=r\]and\[{{R}_{2}}=4r\] \[\frac{T_{1}^{2}}{T_{2}^{2}}=\frac{{{(r)}^{3}}}{{{(4r)}^{3}}}\] \[\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{1}{8}\]You need to login to perform this action.
You will be redirected in
3 sec