A) 1 : 2
B) 1 : 4
C) 1 : 3
D) 4 : 1
E) 2 : 1
Correct Answer: A
Solution :
\[mg=2\,K{{x}_{A}}\] \[mg=K{{x}_{B}}\] \[\frac{{{x}_{A}}}{{{x}_{B}}}=\frac{1}{2}\] \[W=Fx\] So, \[\frac{{{W}_{A}}}{{{W}_{B}}}=\frac{F{{x}_{A}}}{F{{x}_{B}}}=\frac{1}{2}\]You need to login to perform this action.
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