A) 0.50
B) 1.00
C) 1.25
D) 0.05
E) 0.25
Correct Answer: A
Solution :
\[PC{{l}_{5}}PC{{l}_{3}}+C{{l}_{2}}\]4 | 0 | 0 | :initial moles |
4-2=2 | 2 | 2 | : Moles at equilibrium |
\[\frac{2}{4}\] | \[\frac{2}{4}\] | \[\frac{2}{4}\] | : Molar concentrations |
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