A) \[12.5\,\,\Omega \]
B) \[14.5\,\,\Omega \]
C) \[15.6\,\,\Omega \]
D) \[16.6\,\,\Omega \]
E) \[18.6\,\,\Omega \]
Correct Answer: C
Solution :
\[R=\frac{\rho \lambda }{A}\] For given problem \[R\propto {{\lambda }^{2}}\] Hence \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{\lambda _{1}^{2}}{\lambda _{2}^{2}}\] \[{{R}_{2}}={{\left( \frac{{{\lambda }_{2}}}{{{\lambda }_{1}}} \right)}^{2}}\times {{R}_{1}}=15.6\,\Omega \]
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