CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    In a potentiometer experiment, when three cells A, B and C are connected in series the balancing length is found to be 740 cm. If A and B are connected in series balancing length is 440 cm and for B and C connected in series that is 540 cm. Then the emf of\[{{E}_{A}},{{E}_{B}}\]and\[{{E}_{C}}\]are respectively (in volts)

    A)  1, 1.2 and 1.5    

    B)         1, 2 and 3           

    C)         1.5, 2 and 3      

    D)         1.5, 2.5 and 3.5

    E)  1.2, 1.5 and 3.5

    Correct Answer: A

    Solution :

    \[{{V}_{A}}+{{V}_{B}}+{{V}_{C}}\propto 740\] \[{{V}_{A}}+{{V}_{B}}\propto 440\] \[{{V}_{B}}+{{V}_{C}}\propto 540\] Hence, \[{{V}_{A}}:{{V}_{B}}:{{V}_{C}}=1:1.2:1.5\]


You need to login to perform this action.
You will be redirected in 3 sec spinner