A) \[70.7\,V,70.7\,mA\]
B) \[70.7\,V,70.7A\]
C) \[141.4\,V,141.4mA\]
D) \[141.4\,V,\,141.4\,A\]
E) \[100\,\,V,100\,mA\]
Correct Answer: A
Solution :
Given, \[E=100\,\sin 100t\] \[I=100\,\sin \left( 100t+\frac{\pi }{3} \right)\] We knows \[{{E}_{rms}}=\frac{{{E}_{0}}}{\sqrt{2}}\]and \[{{I}_{rms}}=\frac{{{I}_{0}}}{\sqrt{2}}\] Hence, \[{{E}_{rms}}=\frac{100}{\sqrt{2}}=70.7\,V\] \[{{I}_{rms}}=\frac{100}{\sqrt{2}}=70.7\,V\]
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