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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2011

  • question_answer
    The electric field of a plane electromagnetic wave varies with time of amplitude\[2\text{ }V{{m}^{-1}}\]propagating along z-axis. The average energy density of the magnetic field is (in\[J{{m}^{-3}}\])

    A)  \[13.29\times {{10}^{-12}}\]     

    B)         \[8.86\times {{10}^{-12}}\]        

    C)         \[17.72\times {{10}^{-12}}\]     

    D)         \[4.43\times {{10}^{-12}}\]

    E)  \[2.22\times {{10}^{-12}}\]

    Correct Answer: B

    Solution :

    \[U=\frac{1}{2}\times \frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}=\frac{1}{2}\times \frac{1}{2}\times 8.85\times {{10}^{-12}}\times {{(2)}^{2}}\] \[=8.85\times {{10}^{-12}}J{{m}^{-3}}\]


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