A) \[\frac{1}{2}\]
B) \[\frac{\sqrt{3}}{2}\]
C) \[\frac{1}{\sqrt{2}}\]
D) \[\frac{3}{4}\]
E) \[\frac{3}{4}\]
Correct Answer: D
Solution :
\[\phi =\frac{\lambda }{6}=\frac{{{360}^{o}}}{6}={{60}^{o}}\] \[I={{I}_{0}}{{\cos }^{2}}\theta ={{I}_{0}}{{\cos }^{2}}{{60}^{o}}=\frac{3}{4}\times {{I}_{0}}\] \[\frac{I}{{{I}_{0}}}=\frac{3}{4}\]
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