A) 5 mm
B) 0.5 mm
C) 1 mm
D) 10 mm
E) 2.5 mm
Correct Answer: B
Solution :
Difference \[=\frac{2\lambda }{b}\times d\] \[=\frac{2\times 5\times {{10}^{-4}}}{2}\times 100=0.5\,mm\]
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