| I. One atom of oxygen |
| II. One atom of nitrogen |
| III. \[1\times {{10}^{-10}}\]mole of oxygen |
| IV.\[1\times {{10}^{-10}}\]mole of copper |
A) II < I < III < IV
B) I < II < III < IV
C) III < II < IV < I
D) IV < II < III < I
E) II < IV < I < III
Correct Answer: A
Solution :
I. One atom of oxygen \[=16\times 1.66\times {{10}^{-24}}g\] II. One atom of nitrogen\[=14\times 1.66\times {{10}^{-24}}g\] III.\[1\times {{10}^{-10}}\]mole of oxygen\[=32\times 1\times {{10}^{-10}}g\] IV.\[1\times {{10}^{-10}}\]mole of copper\[=63\times 1\times {{10}^{-10}}g\] Thus, the correct order of increasing mass \[II<I<III<IV\]
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