A) 1.5 kJ
B) 0.5 kJ
C) 1.0 kJ
D) 2.5 kJ
E) 2.0 kJ
Correct Answer: C
Solution :
The heat required to raise the temperature of 54 g of aluminium from\[30{}^\circ \]to\[50{}^\circ C\] \[q=nC({{T}_{2}}-{{T}_{1}})\] where n = moles of substance C = molar heat capacity \[=\frac{Mass\text{ }of\text{ }aluminium\text{ }(g)}{Molar\text{ }mass\text{ }of\text{ }aluminium}\times C\times \Delta T\] \[=\frac{54}{27}\times 25\times 20\,J\] \[(\Delta T=50-30=20{}^\circ C)\] \[=1000\text{ }J=1.0\text{ }kJ\]
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