A) \[\frac{1}{2}\]
B) \[\frac{3}{4}\]
C) \[\frac{3}{2}\]
D) \[\frac{2}{3}\]
E) \[\frac{1}{3}\]
Correct Answer: D
Solution :
For the reaction\[A\xrightarrow[{}]{{}}\]products; let the order of reaction is n. Then \[r=k{{[A]}^{n}}\] \[=k\times {{(1.2\times {{10}^{-3}})}^{n}}\] ...(i) At the initial concentration of\[3.24\times {{10}^{-2}}M,\]the rate is\[\theta \]times. Hence, \[9r=k\times {{(3.24\times {{10}^{-2}})}^{n}}\] ...(ii) On dividing, \[\frac{9r}{r}=\frac{k\times {{(3.24\times {{10}^{-2}})}^{n}}}{k\times {{(1.2\times {{10}^{-3}})}^{n}}}\] \[9={{(27)}^{n}}\] \[9={{({{3}^{3}})}^{2/3}}\] \[\therefore \] \[n=\frac{2}{3}\]
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