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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    A reaction is \[A+B\rightleftharpoons C+D\]initially. We start with equal concentration of A arid B. At equilibrium we find the moles of C is two times that of A. What is the equilibrium constant of the reaction?

    A)  1/4                                       

    B)  ½

    C)  4                            

    D)  2

    Correct Answer: C

    Solution :

    \[A+B\rightleftharpoons C+D\] Initital                   \[\because \]\[A=B\] \[\therefore \] Equilibrium constant \[K=\frac{2A.2A}{A.A}=4\]


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