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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    10 litre solution of urea contains 240 g urea. The active mass of urea will be:

    A) \[0.04\]               

    B) \[0.02\]

    C) \[0.4\]                                  

    D) \[0.2\]

    Correct Answer: C

    Solution :

    \[\because \]10 litre of urea solution contains area \[=240gm\] The active mass of urea = ? \[\therefore \] 1 litre of urea solution contains urea \[\frac{240}{10}=24\,gm\]                 \[\therefore \]Active mass\[=\frac{24}{60}=0.4\] [Mol. wt. of urea\[(N{{H}_{2}}CON{{H}_{2}})\]] \[=14+2+12+16+14+2=60\]


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