A) [\[x:x\]is a real number and\[{{x}^{2}}-1=0\,\]}
B) [\[x:x\]is a real number and \[{{x}^{2}}+1=0\]}
C) [\[x:x\]is a real number and\[{{x}^{2}}-9=0\]}
D) [\[x:x\]is a real number and\[{{x}^{2}}=x+2\]}
Correct Answer: B
Solution :
Since \[{{x}^{2}}+1=0\Rightarrow x=\pm 1\]You need to login to perform this action.
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